Mid/SeniorArrayMatrix

Image Overlap

You are given two images, img1 and img2, represented as binary, square matrices of size n x n. A binary matrix has only 0s and 1s as values.

We translate one image however we choose by sliding all the 1 bits left, right, up, and/or down any number of units. We then place it on top of the other image. We can then calculate the overlap by counting the number of positions that have a 1 in both images.

Note also that a translation does not include any kind of rotation. Any 1 bits that are translated outside of the matrix borders are erased.

Return the largest possible overlap.

Example 1
1 1 0
0 1 0
0 1 0

0 0 0
0 1 1
0 0 1
Inputimg1 = [[1,1,0],[0,1,0],[0,1,0]], img2 = [[0,0,0],[0,1,1],[0,0,1]]
Output3
We translate img1 to right by 1 unit and down by 1 unit, giving 3 positions that have a 1 in both images.
Example 2
1

1
Inputimg1 = [[1]], img2 = [[1]]
Output1
Both images contain a single 1 in the same position, so the maximum overlap is 1.

Constraints

  • n == img1.length == img1[i].length
  • n == img2.length == img2[i].length
  • 1 <= n <= 30
  • img1[i][j] is either 0 or 1.
  • img2[i][j] is either 0 or 1.

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