Couples Holding Hands

There are n couples sitting in 2n seats arranged in a row and want to hold hands.

The people and seats are represented by an integer array row where row[i] is the ID of the person sitting in the i^th seat. The couples are numbered in order, the first couple being (0, 1), the second couple being (2, 3), and so on with the last couple being (2n - 2, 2n - 1).

Return the minimum number of swaps so that every couple is sitting side by side. A swap consists of choosing any two people, then they stand up and switch seats.

Example 1
Inputrow = [0,2,1,3]
Output1
We only need to swap the second (row[1]) and third (row[2]) person.
Example 2
Inputrow = [3,2,0,1]
Output0
All couples are already seated side by side.

Constraints

  • 2n == row.length
  • 2 <= n <= 30
  • 0 <= row[i] < 2n
  • All the elements of row are unique.

Asked at 5 companies

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