Handling Sum Queries After Update

You are given two 0-indexed arrays nums1 and nums2 and a 2D array queries of queries. There are three types of queries:

For a query of type 1, queries[i] = [1, l, r]. Flip the values from 0 to 1 and from 1 to 0 in nums1 from index l to index r. Both l and r are 0-indexed.
For a query of type 2, queries[i] = [2, p, 0]. For every index 0 <= i < n, set nums2[i] = nums2[i] + nums1[i] * p.
For a query of type 3, queries[i] = [3, 0, 0]. Find the sum of the elements in nums2.

Return an array containing all the answers to the third type queries.

Example 1

Inputnums1 = [1,0,1], nums2 = [0,0,0], queries = [[1,1,1],[2,1,0],[3,0,0]]

Output[3]

After the first query nums1 becomes [1,1,1], after the second query nums2 becomes [1,1,1], so the answer to the third query is 3.

Example 2

Inputnums1 = [1], nums2 = [5], queries = [[2,0,0],[3,0,0]]

Output[5]

After the first query, nums2 remains [5], so the answer to the second query is 5.

Constraints