Count Negative Numbers in a Sorted Matrix
Given an m x n matrix grid which is sorted in non-increasing order both row-wise and column-wise, return the number of negative numbers in grid.
Follow up: Could you find an O(n + m) solution?
Example 1
4 3 2 -1 3 2 1 -1 1 1 -1 -2 -1 -1 -2 -3
Input
grid = [[4,3,2,-1],[3,2,1,-1],[1,1,-1,-2],[-1,-1,-2,-3]]Output
8There are 8 negatives number in the matrix.
Example 2
3 2 1 0
Input
grid = [[3,2],[1,0]]Output
0There are no negative numbers in the matrix.
Constraints
- m == grid.length
- n == grid[i].length
- 1 <= m, n <= 100
- -100 <= grid[i][j] <= 100