Height of Binary Tree After Subtree Removal Queries

You are given the root of a binary tree with n nodes. Each node is assigned a unique value from 1 to n. You are also given an array queries of size m.

You have to perform m independent queries on the tree where in the i^th query you do the following:

  • Remove the subtree rooted at the node with the value queries[i] from the tree. It is guaranteed that queries[i] will not be equal to the value of the root.

Return an array answer of size m where answer[i] is the height of the tree after performing the i^th query.

Note:

  • The queries are independent, so the tree returns to its initial state after each query.
  • The height of a tree is the number of edges in the longest simple path from the root to some node in the tree.
Example 1
        1
       / \
      3   4
     /   / \
    2   6   5
             \
              7
Inputroot = [1,3,4,2,null,6,5,null,null,null,null,null,7], queries = [4]
Output[2]
After removing the subtree rooted at node 4, the remaining tree has height 2 via the path 1 -> 3 -> 2.
Example 2
            5
          /   \
        8       9
       / \     / \
      2   1   3   7
     / \
    4   6
Inputroot = [5,8,9,2,1,3,7,4,6], queries = [3,2,4,8]
Output[3,2,3,2]
The resulting heights after removing the subtrees rooted at 3, 2, 4, and 8 are 3, 2, 3, and 2 respectively.

Constraints

  • The number of nodes in the tree is n.
  • 2 <= n <= 10^5
  • 1 <= Node.val <= n
  • All the values in the tree are unique.
  • m == queries.length
  • 1 <= m <= min(n, 10^4)
  • 1 <= queries[i] <= n
  • queries[i] != root.val

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