JuniorString

Replace All Digits with Characters

You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices.

You must perform an operation shift(c, x), where c is a character and x is a digit, that returns the x^th character after c.

  • For example, shift('a', 5) = 'f' and shift('x', 0) = 'x'.

For every odd index i, replace the digit s[i] with the result of the shift(s[i-1], s[i]) operation.

Return s after replacing all digits. It is guaranteed that shift(s[i-1], s[i]) will never exceed 'z'.

Note that shift(c, x) is not a preloaded function, but an operation to be implemented as part of the solution.

Example 1
Inputs = "a1c1e1"
Output"abcdef"
The digits are replaced by shifting the preceding letters: a by 1 to b, c by 1 to d, and e by 1 to f.
Example 2
Inputs = "a1b2c3d4e"
Output"abbdcfdhe"
The digits are replaced by shifting the preceding letters: a by 1 to b, b by 2 to d, c by 3 to f, and d by 4 to h.

Constraints

  • 1 <= s.length <= 100
  • s consists only of lowercase English letters and digits.
  • shift(s[i-1], s[i]) <= 'z' for all odd indices i.

Asked at 1 companies

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