Binary Tree Coloring Game
Two players play a turn-based game on a binary tree. You are given the root of this binary tree and the number of nodes n in the tree. n is odd, and each node has a distinct value from 1 to n.
Initially:
- The first player names a value
xwith1 <= x <= n. - The second player names a value
ywith1 <= y <= nandy != x. - The first player colors the node with value
xred. - The second player colors the node with value
yblue.
Then, the players take turns starting with the first player. In each turn, that player chooses a node of their color and colors an uncolored neighbor of the chosen node. A neighbor is either the left child, right child, or parent of the chosen node.
If, and only if, a player cannot choose such a node, they must pass their turn. If both players pass their turn, the game ends, and the winner is the player that colored more nodes.
You are the second player. If it is possible to choose such a y to ensure you win the game, return true. If it is not possible, return false.
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2 3
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8 9 10 11root = [1,2,3,4,5,6,7,8,9,10,11], n = 11, x = 3true 1
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2 3root = [1,2,3], n = 3, x = 1falsey allows the second player to color more nodes than the first player.Constraints
- The number of nodes in the tree is
n. 1 <= x <= n <= 100nis odd.- 1 <= Node.val <= n
- All the values of the tree are unique.